1.5 Determination of Bearing Size
(a) Basic Definitions
In the course of many years of experience with ball bearings and
extensive testing, it has been found that the prediction of the load capacity of a ball
bearing is a statistical event related to the fatigue life of the bearing. This makes the
sizing of ball bearings more difficult than that of many other machine elements.
A basic phenomenon in ball bearings is that ball bearing life has been
found to be inversely proportional to the cube of the bearing load. This means that when
the load is doubled, the life expectancy of the bearing is reduced by a factor of eight.
This phenomenon has been studied extensively and has led to the adoption of an
industry-wide national standard for rating ball bearings pioneered by the American Bearing
Manufacturers Association (formerly Anti-Friction Bearing Manufacturers Association,
Inc.), 1200 19th Street, N.W., Suite 300, Washington, D.C. 20036-2433.
The following represents a summary of the load rating of ball bearings
of less than one inch in diameter, according to ANSI-AFBMA Standard 9-1978: "Load
Rating and Fatigue Life for Ball Bearings" reprinted with the permission of
the American National Standards Institute, Inc., 11 West 42nd Street, 13th Floor, New
York, N.Y. 10036.
Ball bearings were formerly rated on the basis of the compressive stress in the most
heavily loaded ball. Except for static loads, experience has shown that the actual cause
of failure is fatigue. Fatigue
characteristics are thus used for load rating and are dependent to a large extent on
experimental results.
The life of a ball bearing is the life
in hours at some known speed, or the number of revolutions, that the bearing will attain
before the first evidence of fatigue appears on any of the moving elements. Experience has
shown that the life of an individual ball bearing cannot be precisely predicted. Fatigue
characteristics are thus used for load ratings.
Even if ball bearings are properly mounted, adequately lubricated,
protected from foreign matter, and are not subject to extreme operating conditions, they
can ultimately fatigue. Under ideal conditions, the repeated stresses developed in the
contact areas between the balls and the raceways eventually can result in fatigue of the
material which manifests itself as spalling of the load carrying surfaces. In most
applications, the fatigue life is the maximum useful life of a bearing. This fatigue is
the criterion of life used as the basis for the first part of this standard.
The material in the standard which follows assumes bearings having
nontruncated contact area, hardened good quality steel as the bearing material, adequate
lubrication, proper ring support and alignment, nominal internal clearances, and adequate
groove radii. In addition, certain high-speed effects such as ball centrifugal forces and
gyroscopic moments are not considered.
The following nomenclature and definitions are used in life testing of
bearings. A multitude of identical bearings are tested under same conditions:
RATING LIFE
is the life at which 10 percent of bearings have
failed and 90 percent of them are still good. This value is designated as L10 and is expressed in
millions of revolutions.
LIFE of an individual ball bearing is the number of revolutions
(or hours at some given constant speed) designated as L which the bearing runs before the
first evidence of fatigue develops in the material of either ring (or washer) or of any of
the rolling elements.
MEDIAN LIFE is the life at which 50 percent of bearings failed
and 50 percent are still good. It is designated as L50, which is generally not more than five times the RATING LIFE, L10.
BASIC LOAD RATING "C" for a radial or angular contact
ball bearing is the calculated, constant, radial load which a group of apparently
identical bearings with stationary outer ring can theoretically endure for a RATING LIFE
of one million revolutions of the inner ring. For a thrust ball bearing, it is the
calculated, constant, centric, thrust load which a group of apparently identical bearings
can theoretically endure for a RATING LIFE of one million revolutions of one of the
bearing washers. The basic load rating is a reference value only of the base value of one
million revolutions RATING LIFE having been chosen for ease of calculation. Since applied
loading as great as the basic load rating tends to cause local plastic deformation of the
rolling surfaces, it is not anticipated that such heavy loading would normally be applied.
(b) Determination of Basic Load Rating
The basic load rating C for a rating life of one million revolutions
for radial and angular contact ball bearings, except filling slot bearings, with balls not
larger than 1 in. diameter, is given by the equation:

where:
i = number of rows of balls in the bearing
a = nominal angle of contact
(angle between line of action of ball load and plane perpendicular to bearing axis)
Z = number of balls per row
D = ball diameter
fc = a constant from Table
1-2, as determined by the value of (D cos a)/dm
-
dm = pitch diameter of ball
races
NOTE: For balls larger than 1 inch diameter, the exponent for D is 1.4.
To get a better feel for the meaning of one million revolutions, it is
attained in 8 hrs at a speed of 2,084 rpm. Most ball bearings, however, may have intended
life many times exceeding one million revolutions.
In the above formula, dm represents the pitch
diameter of the ball races. It can be expressed as follows:
 
A and B are dimensions
as shown. However, assuming that inner ring and outer ring wall thicknesses are the same,
A becomes outside diameter, and B the bore of the bearing.
Values of fc are shown in Table
1-2
for different values of (D cos a)/dm.
RATING LIFE L10 in millions
of revolutions for a ball bearing application can be calculated from:

where:
C = the basic load rating as previously defined and
P = the load.
(c) Illustrative Examples
Example 1
Consider an ABEC 3 single row, radial ball bearing having 10 balls of
1/16" diameter, 0.300" inner race diameter and 0.452" outer race diameter
in a single shield configuration.
a = 0° (radial bearing)
Z = 10 (number of balls)
D = 1/16" (ball diameter) and

Therefore,
From Table 1-2
this value yields (from third column) a value of fc=4530. Substituting these values in Equation (5) for C, we
obtain:

This means that for a load of P = 143 lbs, the rating life of this ball bearing will be
one million revolutions and 90% of a group of such ball bearings will be expected to
complete or exceed this value.
Table 1-2* Values
of fc

NOTES:
a. When calculating the basic load
rating for a unit consisting of two similar, single row, radial contact ball bearings, in
a duplex mounting, the pair is considered as one, double row, radial contact ball bearing.
b. When calculating the basic load rating for a unit consisting of two, similar, single
row, angular contact ball bearings in a duplex mounting, "Face-to-Face" or
"Back-to-Back", the pair is considered as one, double row, angular contact ball
bearing.
c. When calculating the basic load rating for a unit consisting of two or more similar,
single angular contact ball bearings mounted "in Tandem", properly manufactured
and mounted for equal load distribution, the rating of the combination is the number of
bearings to the 0.7 power times the rating of a single row ball bearing. If the unit may
be treated as a number of individually interchangeable single row bearings, this footnote
(1) c. does not apply.
Use to obtain C in newtons when D is
given in mm.
Use to obtain C in pounds when D is
given in inches.
* Reprinted by permission of the
American National Standards Institute, 11 West 42nd Street, 13th Floor, New York, NY
10036. (from ANSI-AFBMA Std. 9-1978)
Suppose now it is
desired to determine the "L" life of this bearing when operating at 200 rpm and
a load of 50 lbs, the life being evaluated in hours of operation.
Let the life in hours be denoted by L, and let N denote the rpm of the
bearing. We then have:

Substituting N = 200, P = 50 and C = 143 into Equation (8), we obtain L
= 1949 hours.
NOTE: L10 is bearing life in millions of revolutions; L is bearing life
in hours.
A table showing required life at constant operating speed has been given by N. Chironis
("Todays Ball Bearings", Product Engineering, December 12, 1960,
pp. 63-77, table on p. 68). This table is reproduced below with the permission of
McGraw-Hill Book Company, New York, N.Y.

In order to provide
data for larger size bearings as well as additional examples, Table 1-4 is given.
Table 1-4 Dimensions and Basic Load
Ratings for Conrad-Type
Single-Row Radial Ball Bearings

Example 2:
Find the value of C for a 207 radial bearing.
Solution:

From Equation (5) for C:
C = 4550 x 4.327 x 0.2258 = 4440 lbs, load for 1 million
revolutions with 90 percent probability that it will be attained or exceeded.
(d) Relationship between Load and Number of Revolutions
In some cases, it is needed to determine the new value of the permitted
loading when the number of revolutions N is changed.
Experimentally, it was proven that:

where N is number of revolutions and P is radial load.
Furthermore, it was established that

or subsequently:
It has to be made clear that C is the basic load rating in lbs. for a
rating life of 1 million revolutions, and this fact establishes the above relationship.
If a bearing has a rating life expressed in number of revolutions
designated by N, the life of the bearing expressed in hours, designated by L, can be found
from:
N = 60 n L
where n is the actual speed in rpm of the bearing.
Example 3
For Example 2 where we found C = 4440 lbs., find the radial load P1 for a rating life of
500 hours, at 1500 rpm.

Apply: C = 4.440 lbs., n = 1,500 rpm, and L = 500 hrs

(e) Combined Axial and Radial Loads
This condition is dealt with by ANSI-AFBMA Standard 9-1978 which
defines the combined load to be expressed as:
P = C1 (X i Fr + Y Fa)
(11)

where value C1 is a service
factor which is shown in Table 1-5.
In the above equation:
i = race rotation factor equal 1 for inner ring rotation, 1.2 for
outer ring rotation.
Fr and Fa are radial and axial components, respectively, of the load.
X and Y are factors to be used as shown in Table 1-6.
NOTE: Y is the axial or thrust factor determined from the value of
Table 1-6 Values of X
and Y
(1) Two similar, single row, angular
contact ball bearings mounted "Face-to-face" or "Back-to-back" are
considered as one, double row, angular contact bearing.
(2) Values of X, Y and e for a load or contact
angle other than shown in Table 5-5 are obtained by linear interpolation.
(3) Values of X, Y and e shown in Table 5-5 do not apply to filling slot bearings for
applications in which ball-raceway contact areas project substantially into the filling
slot under load.
(4) For single row bearings, when Fa/Fr e, use X = 1
and Y = 0.
* Reprinted by permission of the
American National Standards Institute, 11 West 42nd Street, 13th Floor, New York, NY 10036
(force ANSI-AFBMA Std. 9-1978).
Example 4
For a bearing dealt with in Example 2, assume that it carries a
combined load of 400 lbs radially and 300 lbs axially at 1200 rpm. The outer ring rotates,
and the bearing is subjected to moderate shock. Find the rating life of this bearing in
hours.

NOTE: The impact load on a bearing should not exceed the static
capacity as given by Table 1-4 or the race may be damaged by Brinelling from the balls.
This load may be exceeded somewhat if the bearing is rotating and the duration of the load
is sufficient for the bearing to make one or more complete revolutions while the load is
acting.
Example 5
What change in the loading of a ball bearing will cause the expected
life to be doubled?
Solution:
Let N1 and P1 be the original life and load for the bearing. Let N2 and P2 be the new life and
load.
Then: N2 = 2N1
By Equation (9):

Hence a reduction of the load to 79 percent of its original value will
cause a doubling of the expected life of a ball bearing.
(f) Variable Loading of Bearings
Ball bearings frequently operate under conditions of variable load and
speed. Design calculations should take into account all portions of the work cycle and
should not be based solely on the most severe operating conditions. The work cycle should
be divided into a number of portions in each of which the speed and load can be considered
as constant.
Suppose P1,
P2,... are
the loads on the bearing for successive intervals of the work cycle. Let N1 be the life of the bearing, in revolutions, if operated
exclusively at the constant load P1. Let there be N1 applications of load P1. Then N1/N1 represents the proportion of the life
consumed in this portion of the cycle.
Let N2 be the life of the bearing, in
revolutions, if operated exclusively at load P2. Let there be N2 applications of load P2. Then N2/N2 represents the proportion of the life
consumed by load P2.
A corresponding statement can be made for each portion of the work
cycle. The sum of these proportions represents the total life of the bearing or unity.
Then:

Let Nc be the life of the bearing under the combined loading. Let N1 =
a1Nc where
a1 represents the
proportion of the total life, consumed under load P1. In a similar way, N2 =
a2 Nc, N3 =
a3 Nc, and so on. Substitution in Equation (12) yields:
Using Equation (10):
Combining these last two equations we can obtain:
From previous definition of
a it is obvious that a1 +
a2 + ... must equal unity. The application of this equation will
be demonstrated by the following examples.
Example 6
A ball bearing is to operate on the following work cycle:
Radial load of 1400 lbs at 200 rpm for 25% of the time
Radial load of 2000 lbs at 500 rpm for 20% of the time
Radial load of 800 lbs at 400 rpm for 55% of the time
Total rpm is to be 1100.
Additional conditions:
The inner ring rotates; loads are steady. Find the minimum value of the
basic rating load C for a suitable bearing for this application if the required life is 7
years at 4 hours per day.
Since both the load as well as the speed for the particular load
varies, we have to establish the actual work cycle per minute.

The following table
should be constructed:

A working year is assumed to consist of 250 days.
Total life duration of the bearing expressed in hours will become 7 x
250 x 4 = 7000 hours, whereas this expressed in number of revolutions becomes:

Inputing this data in the formula (13), previously derived in 1.5
(f):

In order to choose the appropriate bearing, we refer to Table 1-4 from
which we find that a bearing such as No. 308 should be satisfactory, keeping in mind there
is but a 90 percent probability that the required life will be attained or exceeded.
Example 7
A 306 radial ball bearing with inner ring rotation has a 10-sec work
cycle as follows:

Find the rating life of this bearing in hours and in years of 250
working days of 2 hours each.
Solution:
Since the bearing chosen is No. 306, from Table 1-4:
Z = 8, D = 0.5 and i = 1.
From Table 1-6
for this value of 200, a value for Y will be 1.45 and X will be 0.56.
From Equation (11) and Table 1-5, for the combined axial and radial
loads with light shock and 2-second duration:

Since P2 is a pure radial load:
P2 = Fr = 600 lbs
The number of revolutions for the 2-second time duration will be:

whereas for the 8-second time duration will be:

The combined total number of revolutions in 10 seconds is:

then,

From formula (13)

Using C = 5120 in Table 1-4 for bearing No. 306:

This is the number of revolutions the bearing will endure. The total
number of revolutions during the 10-second operation was established as being 190.
Therefore, the number of revolutions per minute will be:

From Equation (8):

This expressed in years of operation will become

(g) Static Loading of Bearings
Up to this point we have been dealing with dynamic loading of bearings.
This is the condition when there is relative motion between the rings of the bearings and
the balls that are rotating. If this is not the case, as a result of static concentrated
loads of the balls against the races, the depressions of the balls into the races will
gradually enlarge, and permanent indentations will remain. The static capacity is
ordinarily defined as the maximum allowable static load that does not impair the running
characteristics of the bearing to make it unusable.
This permanent deformation under the balls is known as Brinnelling and
takes place at moderate to high loads. The magnitude of the permissible load is found by
methods given in the standards. Calculations for the bearings of Table 1-4 have been made
and are shown in the column headed Pst.
When very smooth and quiet operation is required, the loading should be
no more than about one-half the static capacity.
Back and forth rotation of the shaft through small angles can cause
early failure of bearings unless the load is very light. Lubrication is difficult because
the oil or grease may not be replenished back of a ball or roller before the motion is
reversed.
(h) Effect of Increased Confidence Levels
When a bearing is installed there is no way of knowing whether
it is one of the 90 percent that are good or one of the 10 percent that will not attain
the rating life. In other words, one can have but 90 percent confidence that the bearing
will achieve or exceed its rating life, usually designated L10.
In some cases a greater degree of reliability is required. The expected life will of
course be reduced as the reliability is made higher. Let an adjusting factor a1 be taken such that life
Ln is equal
to a1 L10. Factors a1 for different values of
the reliability are given in Table 1-7. Life L10 is the rating life.

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